$$ % Dirac notation \newcommand{\ket}[1]{\left|#1\right\rangle} \newcommand{\bra}[1]{\left\langle#1\right|} \newcommand{\braket}[2]{\left\langle#1\middle|#2\right\rangle} \newcommand{\expect}[1]{\left\langle#1\right\rangle} % Common operators \newcommand{\tr}{\operatorname{tr}} \newcommand{\Tr}{\operatorname{Tr}} \DeclareMathOperator*{\argmin}{arg\,min} \DeclareMathOperator*{\argmax}{arg\,max} % Complexity \newcommand{\bigO}[1]{\mathcal{O}\!\left(#1\right)} $$

Doppler Selectivity Explorer

Interactive tools for understanding velocity-enabled quantum computing

1. Doppler Shift Explorer

How does atom velocity translate into a frequency shift seen by the laser? Drag the sliders to find out.

Tip

Try this: Increase the velocity until the two peaks no longer overlap. At what velocity does the Doppler shift exceed the linewidth (~5 kHz)? This is the regime where velocity-based addressing becomes possible.


2. Velocity Selectivity: Infidelity on Stationary Atoms

The central result: when a laser drives a \(\pi\)-pulse on moving atoms (resonant), how much does it accidentally affect stationary atoms (off-resonant)? The infidelity depends on the distance \(d\) the atom travels during the pulse.

\[ \text{infidelity} = \frac{\pi^2}{4}\,\operatorname{sinc}^2\!\left(\frac{\pi}{2}\sqrt{1 + \left(\frac{2d}{\lambda_0}\right)^2}\right) \]

Note

Green diamonds mark zero-crossing distances where infidelity vanishes exactly – these correspond to complete \(2\pi\) rotations on the stationary atoms. Operating near these sweet spots gives the best selectivity.


3. Rabi Oscillations Simulator

Watch how resonant (moving) and detuned (stationary) atoms evolve differently under a driving laser field.

Tip

Key insight: Set the detuning to zero and watch both curves overlap – no selectivity. Now increase the detuning. The orange (stationary) curve shrinks in amplitude and oscillates faster. At the \(\pi\)-time, the moving atoms are fully excited while the stationary atoms barely budge. That is velocity-based quantum gate selectivity.